16x^2-45x+12=0

Solution for 16x^2-45x+12=0 equation:

16x^2-45x+12=0

a = 16; b = -45; c = +12;
Δ = b2-4ac
Δ = -452-4·16·12
Δ = 1257
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-45)-\sqrt{1257}}{2*16}=\frac{45-\sqrt{1257}}{32}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-45)+\sqrt{1257}}{2*16}=\frac{45+\sqrt{1257}}{32}
$